Base | Representation |
---|---|
bin | 111110111000111011… |
… | …1110111000101100111 |
3 | 110220121011210011121011 |
4 | 1331301313313011213 |
5 | 4203042420031033 |
6 | 142013153403051 |
7 | 12520526633116 |
oct | 1756167670547 |
9 | 426534704534 |
10 | 135054455143 |
11 | 523047a0093 |
12 | 22211569487 |
13 | c9740bb5aa |
14 | 67728a3c7d |
15 | 37a6974ccd |
hex | 1f71df7167 |
135054455143 has 4 divisors (see below), whose sum is σ = 135061988248. Its totient is φ = 135046922040.
The previous prime is 135054455101. The next prime is 135054455147. The reversal of 135054455143 is 341554450531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135054455143 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135054455096 and 135054455105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135054455147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3739596 + ... + 3775537.
It is an arithmetic number, because the mean of its divisors is an integer number (33765497062).
Almost surely, 2135054455143 is an apocalyptic number.
135054455143 is a deficient number, since it is larger than the sum of its proper divisors (7533105).
135054455143 is an equidigital number, since it uses as much as digits as its factorization.
135054455143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7533104.
The product of its (nonzero) digits is 360000, while the sum is 40.
The spelling of 135054455143 in words is "one hundred thirty-five billion, fifty-four million, four hundred fifty-five thousand, one hundred forty-three".
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