Base | Representation |
---|---|
bin | 111110111001010000… |
… | …0100100000100001111 |
3 | 110220121220212021002001 |
4 | 1331302200210010033 |
5 | 4203103133001020 |
6 | 142014214213131 |
7 | 12521016423013 |
oct | 1756240440417 |
9 | 426556767061 |
10 | 135065125135 |
11 | 5230a818666 |
12 | 222150541a7 |
13 | c9763860b5 |
14 | 6774080543 |
15 | 37a788150a |
hex | 1f7282410f |
135065125135 has 16 divisors (see below), whose sum is σ = 169254614016. Its totient is φ = 103274990368.
The previous prime is 135065125133. The next prime is 135065125159. The reversal of 135065125135 is 531521560531.
It is a cyclic number.
It is not a de Polignac number, because 135065125135 - 21 = 135065125133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135065125094 and 135065125103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135065125133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 298999 + ... + 599608.
It is an arithmetic number, because the mean of its divisors is an integer number (10578413376).
Almost surely, 2135065125135 is an apocalyptic number.
135065125135 is a deficient number, since it is larger than the sum of its proper divisors (34189488881).
135065125135 is a wasteful number, since it uses less digits than its factorization.
135065125135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 899942.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 135065125135 its reverse (531521560531), we get a palindrome (666586685666).
The spelling of 135065125135 in words is "one hundred thirty-five billion, sixty-five million, one hundred twenty-five thousand, one hundred thirty-five".
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