Base | Representation |
---|---|
bin | 111110111001011101… |
… | …1001011000001100111 |
3 | 110220122101222122102020 |
4 | 1331302323023001213 |
5 | 4203111424203310 |
6 | 142015023514223 |
7 | 12521132624145 |
oct | 1756273130147 |
9 | 426571878366 |
10 | 135072100455 |
11 | 52313752296 |
12 | 22217458973 |
13 | c977958cc6 |
14 | 6774d78595 |
15 | 37a82ad170 |
hex | 1f72ecb067 |
135072100455 has 8 divisors (see below), whose sum is σ = 216115360752. Its totient is φ = 72038453568.
The previous prime is 135072100447. The next prime is 135072100487. The reversal of 135072100455 is 554001270531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 135072100455 - 23 = 135072100447 is a prime.
It is a super-2 number, since 2×1350721004552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4502403334 + ... + 4502403363.
It is an arithmetic number, because the mean of its divisors is an integer number (27014420094).
Almost surely, 2135072100455 is an apocalyptic number.
135072100455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135072100455 is a deficient number, since it is larger than the sum of its proper divisors (81043260297).
135072100455 is an equidigital number, since it uses as much as digits as its factorization.
135072100455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9004806705.
The product of its (nonzero) digits is 21000, while the sum is 33.
Adding to 135072100455 its reverse (554001270531), we get a palindrome (689073370986).
The spelling of 135072100455 in words is "one hundred thirty-five billion, seventy-two million, one hundred thousand, four hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •