Base | Representation |
---|---|
bin | 111110111001110111… |
… | …1000010110011001111 |
3 | 110220200100120111002110 |
4 | 1331303233002303033 |
5 | 4203123414321010 |
6 | 142020231155103 |
7 | 12521356326654 |
oct | 1756357026317 |
9 | 426610514073 |
10 | 135085698255 |
11 | 5232039a542 |
12 | 2221bb15a93 |
13 | c97a70a341 |
14 | 6776ab7c2b |
15 | 37a9597120 |
hex | 1f73bc2ccf |
135085698255 has 16 divisors (see below), whose sum is σ = 216515654784. Its totient is φ = 71919526560.
The previous prime is 135085698203. The next prime is 135085698257. The reversal of 135085698255 is 552896580531.
It is not a de Polignac number, because 135085698255 - 215 = 135085665487 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135085698195 and 135085698204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135085698257) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7877349 + ... + 7894478.
It is an arithmetic number, because the mean of its divisors is an integer number (13532228424).
Almost surely, 2135085698255 is an apocalyptic number.
135085698255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135085698255 is a deficient number, since it is larger than the sum of its proper divisors (81429956529).
135085698255 is a wasteful number, since it uses less digits than its factorization.
135085698255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15772406.
The product of its (nonzero) digits is 12960000, while the sum is 57.
The spelling of 135085698255 in words is "one hundred thirty-five billion, eighty-five million, six hundred ninety-eight thousand, two hundred fifty-five".
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