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135100047 = 350218969
BaseRepresentation
bin10000000110101…
…11011010001111
3100102012210102110
420003113122033
5234041200142
621223355103
73230221455
oct1003273217
9312183373
10135100047
116a295735
12392b2a93
1321cb2c74
1413d2a9d5
15bcd999c
hex80d768f

135100047 has 8 divisors (see below), whose sum is σ = 180189360. Its totient is φ = 90038720.

The previous prime is 135100001. The next prime is 135100079. The reversal of 135100047 is 740001531.

135100047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135100047 - 26 = 135099983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135099996 and 135100032.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135100747) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10579 + ... + 19547.

It is an arithmetic number, because the mean of its divisors is an integer number (22523670).

Almost surely, 2135100047 is an apocalyptic number.

135100047 is a deficient number, since it is larger than the sum of its proper divisors (45089313).

135100047 is an equidigital number, since it uses as much as digits as its factorization.

135100047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13993.

The product of its (nonzero) digits is 420, while the sum is 21.

The square root of 135100047 is about 11623.2545786453. The cubic root of 135100047 is about 513.1194771286.

Adding to 135100047 its reverse (740001531), we get a palindrome (875101578).

The spelling of 135100047 in words is "one hundred thirty-five million, one hundred thousand, forty-seven".

Divisors: 1 3 5021 8969 15063 26907 45033349 135100047