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135100253051 = 696719391453
BaseRepresentation
bin111110111010010011…
…0100100001101111011
3110220201100221221111222
41331310212210031323
54203141131044201
6142021511142255
712521624126531
oct1756446441573
9426640857458
10135100253051
11523286307a5
122222497498b
13c98073514a
1467789c6151
1537aa9be91b
hex1f749a437b

135100253051 has 4 divisors (see below), whose sum is σ = 135119651472. Its totient is φ = 135080854632.

The previous prime is 135100253033. The next prime is 135100253059. The reversal of 135100253051 is 150352001531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135100253051 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135100253051.

It is not an unprimeable number, because it can be changed into a prime (135100253059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9688760 + ... + 9702693.

It is an arithmetic number, because the mean of its divisors is an integer number (33779912868).

Almost surely, 2135100253051 is an apocalyptic number.

135100253051 is a deficient number, since it is larger than the sum of its proper divisors (19398421).

135100253051 is an equidigital number, since it uses as much as digits as its factorization.

135100253051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19398420.

The product of its (nonzero) digits is 2250, while the sum is 26.

Adding to 135100253051 its reverse (150352001531), we get a palindrome (285452254582).

The spelling of 135100253051 in words is "one hundred thirty-five billion, one hundred million, two hundred fifty-three thousand, fifty-one".

Divisors: 1 6967 19391453 135100253051