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1351041730341 = 3450347243447
BaseRepresentation
bin10011101010010000010…
…111001100011100100101
311210011021102101000020020
4103222100113030130211
5134113413140332331
62512354321025353
7166416034141002
oct23522027143445
94704242330206
101351041730341
11480a78920706
12199a11185259
139a530925644
14495683aa8a9
1525224e90c96
hex13a905cc725

1351041730341 has 4 divisors (see below), whose sum is σ = 1801388973792. Its totient is φ = 900694486892.

The previous prime is 1351041730333. The next prime is 1351041730343. The reversal of 1351041730341 is 1430371401531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1351041730341 - 23 = 1351041730333 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1351041730343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225173621721 + ... + 225173621726.

It is an arithmetic number, because the mean of its divisors is an integer number (450347243448).

Almost surely, 21351041730341 is an apocalyptic number.

It is an amenable number.

1351041730341 is a deficient number, since it is larger than the sum of its proper divisors (450347243451).

1351041730341 is an equidigital number, since it uses as much as digits as its factorization.

1351041730341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450347243450.

The product of its (nonzero) digits is 15120, while the sum is 33.

The spelling of 1351041730341 in words is "one trillion, three hundred fifty-one billion, forty-one million, seven hundred thirty thousand, three hundred forty-one".

Divisors: 1 3 450347243447 1351041730341