Base | Representation |
---|---|
bin | 10011101010010100000… |
… | …101100111001111000101 |
3 | 11210011102202222100010001 |
4 | 103222110011213033011 |
5 | 134114030140332331 |
6 | 2512404432401301 |
7 | 166420423316515 |
oct | 23522405471705 |
9 | 4704382870101 |
10 | 1351104230341 |
11 | 4810001298a8 |
12 | 199a2a0a6231 |
13 | 9a5408694a8 |
14 | 495727d9845 |
15 | 2522a6d9561 |
hex | 13a941673c5 |
1351104230341 has 8 divisors (see below), whose sum is σ = 1360852436160. Its totient is φ = 1341356425248.
The previous prime is 1351104230339. The next prime is 1351104230351. The reversal of 1351104230341 is 1430324011531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1351104230341 - 21 = 1351104230339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351104230351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11440305 + ... + 11557801.
It is an arithmetic number, because the mean of its divisors is an integer number (170106554520).
Almost surely, 21351104230341 is an apocalyptic number.
It is an amenable number.
1351104230341 is a deficient number, since it is larger than the sum of its proper divisors (9748205819).
1351104230341 is a wasteful number, since it uses less digits than its factorization.
1351104230341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200363.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1351104230341 its reverse (1430324011531), we get a palindrome (2781428241872).
The spelling of 1351104230341 in words is "one trillion, three hundred fifty-one billion, one hundred four million, two hundred thirty thousand, three hundred forty-one".
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