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13512204311 = 229213127689
BaseRepresentation
bin11001001010110001…
…11110000000010111
31021212200121002200112
430211120332000113
5210133111014221
610112445233235
7655562561444
oct144530760027
937780532615
1013512204311
115804318101
12275126281b
13137453aa88
149227ba9cb
155413cb15b
hex32563e017

13512204311 has 8 divisors (see below), whose sum is σ = 13578068400. Its totient is φ = 13446400320.

The previous prime is 13512204257. The next prime is 13512204341. The reversal of 13512204311 is 11340221531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13512204311 - 218 = 13511942167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13512204341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474155 + ... + 501843.

It is an arithmetic number, because the mean of its divisors is an integer number (1697258550).

Almost surely, 213512204311 is an apocalyptic number.

13512204311 is a deficient number, since it is larger than the sum of its proper divisors (65864089).

13512204311 is a wasteful number, since it uses less digits than its factorization.

13512204311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30049.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13512204311 its reverse (11340221531), we get a palindrome (24852425842).

It can be divided in two parts, 1351220 and 4311, that added together give a palindrome (1355531).

The spelling of 13512204311 in words is "thirteen billion, five hundred twelve million, two hundred four thousand, three hundred eleven".

Divisors: 1 229 2131 27689 487999 6340781 59005259 13512204311