Base | Representation |
---|---|
bin | 10011101010011101000… |
… | …001000011011011100011 |
3 | 11210011211012211221200110 |
4 | 103222131001003123203 |
5 | 134114332012430201 |
6 | 2512431343222403 |
7 | 166424222513412 |
oct | 23523501033343 |
9 | 4704735757613 |
10 | 1351254030051 |
11 | 481077744612 |
12 | 199a702a7a03 |
13 | 9a5658c8183 |
14 | 49588671479 |
15 | 252389296d6 |
hex | 13a9d0436e3 |
1351254030051 has 8 divisors (see below), whose sum is σ = 1806864179904. Its totient is φ = 898239950120.
The previous prime is 1351254030029. The next prime is 1351254030103. The reversal of 1351254030051 is 1500304521531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1351254030051 - 218 = 1351253767907 is a prime.
It is a super-2 number, since 2×13512540300512 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1351254031051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 649016265 + ... + 649018346.
It is an arithmetic number, because the mean of its divisors is an integer number (225858022488).
Almost surely, 21351254030051 is an apocalyptic number.
1351254030051 is a deficient number, since it is larger than the sum of its proper divisors (455610149853).
1351254030051 is a wasteful number, since it uses less digits than its factorization.
1351254030051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1298034961.
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 1351254030051 its reverse (1500304521531), we get a palindrome (2851558551582).
The spelling of 1351254030051 in words is "one trillion, three hundred fifty-one billion, two hundred fifty-four million, thirty thousand, fifty-one".
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