Base | Representation |
---|---|
bin | 11001001010111010… |
… | …01010000000100011 |
3 | 1021212202122212111120 |
4 | 30211131022000203 |
5 | 210133401131201 |
6 | 10112524543323 |
7 | 655605113034 |
oct | 144535120043 |
9 | 37782585446 |
10 | 13513302051 |
11 | 58049a7927 |
12 | 27516b1b43 |
13 | 1374833622 |
14 | 9229c4a8b |
15 | 541546536 |
hex | 32574a023 |
13513302051 has 4 divisors (see below), whose sum is σ = 18017736072. Its totient is φ = 9008868032.
The previous prime is 13513302029. The next prime is 13513302067. The reversal of 13513302051 is 15020331531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13513302051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13513352051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2252217006 + ... + 2252217011.
It is an arithmetic number, because the mean of its divisors is an integer number (4504434018).
Almost surely, 213513302051 is an apocalyptic number.
13513302051 is a deficient number, since it is larger than the sum of its proper divisors (4504434021).
13513302051 is an equidigital number, since it uses as much as digits as its factorization.
13513302051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4504434020.
The product of its (nonzero) digits is 1350, while the sum is 24.
Adding to 13513302051 its reverse (15020331531), we get a palindrome (28533633582).
The spelling of 13513302051 in words is "thirteen billion, five hundred thirteen million, three hundred two thousand, fifty-one".
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