Search a number
-
+
135144403 = 604722349
BaseRepresentation
bin10000000111000…
…10001111010011
3100102022001021021
420003202033103
5234044110103
621224340311
73230465002
oct1003421723
9312261237
10135144403
116a315a99
1239314697
1321cca204
1413d3cc39
15bce7bbd
hex80e23d3

135144403 has 4 divisors (see below), whose sum is σ = 135172800. Its totient is φ = 135116008.

The previous prime is 135144367. The next prime is 135144419. The reversal of 135144403 is 304441531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304441531 = 2291329439.

It is a cyclic number.

It is not a de Polignac number, because 135144403 - 217 = 135013331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135144433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5128 + ... + 17221.

It is an arithmetic number, because the mean of its divisors is an integer number (33793200).

Almost surely, 2135144403 is an apocalyptic number.

135144403 is a deficient number, since it is larger than the sum of its proper divisors (28397).

135144403 is an equidigital number, since it uses as much as digits as its factorization.

135144403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28396.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 135144403 is about 11625.1624934880. The cubic root of 135144403 is about 513.1756267196.

Adding to 135144403 its reverse (304441531), we get a palindrome (439585934).

It can be divided in two parts, 1351 and 44403, that added together give a palindrome (45754).

The spelling of 135144403 in words is "one hundred thirty-five million, one hundred forty-four thousand, four hundred three".

Divisors: 1 6047 22349 135144403