1351630433441 has 4 divisors (see below), whose sum is σ = 1353196634112. Its totient is φ = 1350064232772.

The previous prime is 1351630433431. The next prime is 1351630433471. The reversal of 1351630433441 is 1443340361531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1351630433441 - 2²² = 1351626239137 is a prime.

It is a super-2 number, since 2×1351630433441² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1351630433395 and 1351630433404.

It is not an unprimeable number, because it can be changed into a prime (1351630433431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783099041 + ... + 783100766.

It is an arithmetic number, because the mean of its divisors is an integer number (338299158528).

Almost surely, 2^{1351630433441} is an apocalyptic number.

It is an amenable number.

1351630433441 is a deficient number, since it is larger than the sum of its proper divisors (1566200671).

1351630433441 is an equidigital number, since it uses as much as digits as its factorization.

1351630433441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1566200670.

The product of its (nonzero) digits is 155520, while the sum is 38.

Adding to 1351630433441 its reverse (1443340361531), we get a palindrome (2794970794972).

The spelling of 1351630433441 in words is "one trillion, three hundred fifty-one billion, six hundred thirty million, four hundred thirty-three thousand, four hundred forty-one".