Search a number
-
+
1351643505151 = 2351574922801
BaseRepresentation
bin10011101010110100001…
…110110010000111111111
311210012211100201100002011
4103222310032302013333
5134121131214131101
62512534135112051
7166436662141342
oct23526416620777
94705740640064
101351643505151
11481257580a65
12199b5a812627
139a5c84c3004
14495c4296459
152525cc0e751
hex13ab43b21ff

1351643505151 has 4 divisors (see below), whose sum is σ = 1352218430304. Its totient is φ = 1351068580000.

The previous prime is 1351643505139. The next prime is 1351643505187. The reversal of 1351643505151 is 1515053461531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1351643505151 - 217 = 1351643374079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1351643505851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287459050 + ... + 287463751.

It is an arithmetic number, because the mean of its divisors is an integer number (338054607576).

Almost surely, 21351643505151 is an apocalyptic number.

1351643505151 is a deficient number, since it is larger than the sum of its proper divisors (574925153).

1351643505151 is an equidigital number, since it uses as much as digits as its factorization.

1351643505151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 574925152.

The product of its (nonzero) digits is 135000, while the sum is 40.

Adding to 1351643505151 its reverse (1515053461531), we get a palindrome (2866696966682).

The spelling of 1351643505151 in words is "one trillion, three hundred fifty-one billion, six hundred forty-three million, five hundred five thousand, one hundred fifty-one".

Divisors: 1 2351 574922801 1351643505151