Base | Representation |
---|---|
bin | 10011101010110100001… |
… | …110110010000111111111 |
3 | 11210012211100201100002011 |
4 | 103222310032302013333 |
5 | 134121131214131101 |
6 | 2512534135112051 |
7 | 166436662141342 |
oct | 23526416620777 |
9 | 4705740640064 |
10 | 1351643505151 |
11 | 481257580a65 |
12 | 199b5a812627 |
13 | 9a5c84c3004 |
14 | 495c4296459 |
15 | 2525cc0e751 |
hex | 13ab43b21ff |
1351643505151 has 4 divisors (see below), whose sum is σ = 1352218430304. Its totient is φ = 1351068580000.
The previous prime is 1351643505139. The next prime is 1351643505187. The reversal of 1351643505151 is 1515053461531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1351643505151 - 217 = 1351643374079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351643505851) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287459050 + ... + 287463751.
It is an arithmetic number, because the mean of its divisors is an integer number (338054607576).
Almost surely, 21351643505151 is an apocalyptic number.
1351643505151 is a deficient number, since it is larger than the sum of its proper divisors (574925153).
1351643505151 is an equidigital number, since it uses as much as digits as its factorization.
1351643505151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 574925152.
The product of its (nonzero) digits is 135000, while the sum is 40.
Adding to 1351643505151 its reverse (1515053461531), we get a palindrome (2866696966682).
The spelling of 1351643505151 in words is "one trillion, three hundred fifty-one billion, six hundred forty-three million, five hundred five thousand, one hundred fifty-one".
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