Base | Representation |
---|---|
bin | 10011101010110111111… |
… | …001110101000100010111 |
3 | 11210012222122122202012101 |
4 | 103222313321311010113 |
5 | 134121243002333142 |
6 | 2512544215502531 |
7 | 166441340645461 |
oct | 23526771650427 |
9 | 4705878582171 |
10 | 1351705121047 |
11 | 481289335996 |
12 | 199b77387a47 |
13 | 9a6081b7618 |
14 | 495cc535131 |
15 | 252633310b7 |
hex | 13ab7e75117 |
1351705121047 has 4 divisors (see below), whose sum is σ = 1359799163856. Its totient is φ = 1343611078240.
The previous prime is 1351705121023. The next prime is 1351705121147. The reversal of 1351705121047 is 7401215071531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351705121047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1351705120997 and 1351705121015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351705121147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4047021154 + ... + 4047021487.
It is an arithmetic number, because the mean of its divisors is an integer number (339949790964).
Almost surely, 21351705121047 is an apocalyptic number.
1351705121047 is a deficient number, since it is larger than the sum of its proper divisors (8094042809).
1351705121047 is an equidigital number, since it uses as much as digits as its factorization.
1351705121047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8094042808.
The product of its (nonzero) digits is 29400, while the sum is 37.
The spelling of 1351705121047 in words is "one trillion, three hundred fifty-one billion, seven hundred five million, one hundred twenty-one thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •