Base | Representation |
---|---|
bin | 11001001011101101… |
… | …10011011101100101 |
3 | 1021220020022110021011 |
4 | 30211312303131211 |
5 | 210142111303240 |
6 | 10113325022221 |
7 | 656016214543 |
oct | 144566633545 |
9 | 37806273234 |
10 | 13520025445 |
11 | 580877a253 |
12 | 27539b4971 |
13 | 1376048974 |
14 | 923854d93 |
15 | 541e236ea |
hex | 325db3765 |
13520025445 has 8 divisors (see below), whose sum is σ = 16229991960. Its totient is φ = 10812046080.
The previous prime is 13520025437. The next prime is 13520025451. The reversal of 13520025445 is 54452002531.
It can be written as a sum of positive squares in 4 ways, for example, as 7354949121 + 6165076324 = 85761^2 + 78518^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13520025445 - 23 = 13520025437 is a prime.
It is a super-3 number, since 3×135200254453 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481776 + ... + 509065.
It is an arithmetic number, because the mean of its divisors is an integer number (2028748995).
Almost surely, 213520025445 is an apocalyptic number.
It is an amenable number.
13520025445 is a deficient number, since it is larger than the sum of its proper divisors (2709966515).
13520025445 is an equidigital number, since it uses as much as digits as its factorization.
13520025445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 993575.
The product of its (nonzero) digits is 24000, while the sum is 31.
Adding to 13520025445 its reverse (54452002531), we get a palindrome (67972027976).
The spelling of 13520025445 in words is "thirteen billion, five hundred twenty million, twenty-five thousand, four hundred forty-five".
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