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1352050341241 = 531371571186033
BaseRepresentation
bin10011101011001100011…
…110101111010101111001
311210020212201020202021111
4103223030132233111321
5134122444341404431
62513042351040321
7166453032164365
oct23531436572571
94706781222244
101352050341241
11481446195a36
1219a052b100a1
139a661889022
144962231a2a5
15252837c37b1
hex13acc7af579

1352050341241 has 16 divisors (see below), whose sum is σ = 1396455408144. Its totient is φ = 1308468455424.

The previous prime is 1352050341193. The next prime is 1352050341253. The reversal of 1352050341241 is 1421430502531.

It can be written as a sum of positive squares in 8 ways, for example, as 64742258025 + 1287308083216 = 254445^2 + 1134596^2 .

It is a cyclic number.

It is not a de Polignac number, because 1352050341241 - 211 = 1352050339193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1352050341841) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 546961 + ... + 1732993.

It is an arithmetic number, because the mean of its divisors is an integer number (87278463009).

Almost surely, 21352050341241 is an apocalyptic number.

It is an amenable number.

1352050341241 is a deficient number, since it is larger than the sum of its proper divisors (44405066903).

1352050341241 is a wasteful number, since it uses less digits than its factorization.

1352050341241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1186380.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1352050341241 its reverse (1421430502531), we get a palindrome (2773480843772).

The spelling of 1352050341241 in words is "one trillion, three hundred fifty-two billion, fifty million, three hundred forty-one thousand, two hundred forty-one".

Divisors: 1 53 137 157 7261 8321 21509 1139977 1186033 62859749 162486521 186207181 8611785613 9868980593 25510383797 1352050341241