Base | Representation |
---|---|
bin | 10011101011001100011… |
… | …110101111010101111001 |
3 | 11210020212201020202021111 |
4 | 103223030132233111321 |
5 | 134122444341404431 |
6 | 2513042351040321 |
7 | 166453032164365 |
oct | 23531436572571 |
9 | 4706781222244 |
10 | 1352050341241 |
11 | 481446195a36 |
12 | 19a052b100a1 |
13 | 9a661889022 |
14 | 4962231a2a5 |
15 | 252837c37b1 |
hex | 13acc7af579 |
1352050341241 has 16 divisors (see below), whose sum is σ = 1396455408144. Its totient is φ = 1308468455424.
The previous prime is 1352050341193. The next prime is 1352050341253. The reversal of 1352050341241 is 1421430502531.
It can be written as a sum of positive squares in 8 ways, for example, as 64742258025 + 1287308083216 = 254445^2 + 1134596^2 .
It is a cyclic number.
It is not a de Polignac number, because 1352050341241 - 211 = 1352050339193 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1352050341841) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 546961 + ... + 1732993.
It is an arithmetic number, because the mean of its divisors is an integer number (87278463009).
Almost surely, 21352050341241 is an apocalyptic number.
It is an amenable number.
1352050341241 is a deficient number, since it is larger than the sum of its proper divisors (44405066903).
1352050341241 is a wasteful number, since it uses less digits than its factorization.
1352050341241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1186380.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1352050341241 its reverse (1421430502531), we get a palindrome (2773480843772).
The spelling of 1352050341241 in words is "one trillion, three hundred fifty-two billion, fifty million, three hundred forty-one thousand, two hundred forty-one".
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