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13521002155 = 52704200431
BaseRepresentation
bin11001001011110101…
…00001111010101011
31021220022011002001121
430211322201322223
5210142334032110
610113402000111
7656030423233
oct144572417253
937808132047
1013521002155
115809287051
1227541a6037
1313762cb3bb
14923a2acc3
15542067cda
hex325ea1eab

13521002155 has 4 divisors (see below), whose sum is σ = 16225202592. Its totient is φ = 10816801720.

The previous prime is 13521002147. The next prime is 13521002177. The reversal of 13521002155 is 55120012531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55120012531 = 59239306097.

It is not a de Polignac number, because 13521002155 - 23 = 13521002147 is a prime.

It is a super-3 number, since 3×135210021553 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1352100211 + ... + 1352100220.

It is an arithmetic number, because the mean of its divisors is an integer number (4056300648).

Almost surely, 213521002155 is an apocalyptic number.

13521002155 is a deficient number, since it is larger than the sum of its proper divisors (2704200437).

13521002155 is an equidigital number, since it uses as much as digits as its factorization.

13521002155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2704200436.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 13521002155 its reverse (55120012531), we get a palindrome (68641014686).

The spelling of 13521002155 in words is "thirteen billion, five hundred twenty-one million, two thousand, one hundred fifty-five".

Divisors: 1 5 2704200431 13521002155