135215240143253 has 4 divisors (see below), whose sum is σ = 142331831729760. Its totient is φ = 128098648556748.

The previous prime is 135215240143223. The next prime is 135215240143327. The reversal of 135215240143253 is 352341042512531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135215240143253 is a prime.

It is a super-2 number, since 2×135215240143253² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135215240143253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135215240143223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3558295793225 + ... + 3558295793262.

It is an arithmetic number, because the mean of its divisors is an integer number (35582957932440).

Almost surely, 2^{135215240143253} is an apocalyptic number.

It is an amenable number.

135215240143253 is a deficient number, since it is larger than the sum of its proper divisors (7116591586507).

135215240143253 is an equidigital number, since it uses as much as digits as its factorization.

135215240143253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7116591586506.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 135215240143253 its reverse (352341042512531), we get a palindrome (487556282655784).

The spelling of 135215240143253 in words is "one hundred thirty-five trillion, two hundred fifteen billion, two hundred forty million, one hundred forty-three thousand, two hundred fifty-three".