Base | Representation |
---|---|
bin | 11110101111110000010110… |
… | …010111010010100100101010 |
3 | 122201210012112010012211102012 |
4 | 132233300112113102210222 |
5 | 120210443430120121102 |
6 | 1155332351333235522 |
7 | 40324356052312400 |
oct | 3657602627224452 |
9 | 581705463184365 |
10 | 135223125551402 |
11 | 3a0a4895128a39 |
12 | 131bb193192ba2 |
13 | 5a5b641a46435 |
14 | 2556b97077470 |
15 | 10976e559e752 |
hex | 7afc165d292a |
135223125551402 has 48 divisors (see below), whose sum is σ = 236074394790720. Its totient is φ = 57922358199552.
The previous prime is 135223125551377. The next prime is 135223125551407. The reversal of 135223125551402 is 204155521322531.
It is a self number, because there is not a number n which added to its sum of digits gives 135223125551402.
It is not an unprimeable number, because it can be changed into a prime (135223125551407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1942184363 + ... + 1942253985.
It is an arithmetic number, because the mean of its divisors is an integer number (4918216558140).
Almost surely, 2135223125551402 is an apocalyptic number.
135223125551402 is a deficient number, since it is larger than the sum of its proper divisors (100851269239318).
135223125551402 is a wasteful number, since it uses less digits than its factorization.
135223125551402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79755 (or 79748 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 135223125551402 its reverse (204155521322531), we get a palindrome (339378646873933).
The spelling of 135223125551402 in words is "one hundred thirty-five trillion, two hundred twenty-three billion, one hundred twenty-five million, five hundred fifty-one thousand, four hundred two".
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