Base | Representation |
---|---|
bin | 111110111110001110… |
… | …1100001101010110001 |
3 | 110221001120001111221212 |
4 | 1331330131201222301 |
5 | 4203423404213131 |
6 | 142042541125505 |
7 | 12525114615152 |
oct | 1757435415261 |
9 | 427046044855 |
10 | 135232101041 |
11 | 52395aa5084 |
12 | 22260b59895 |
13 | c9a1b49acb |
14 | 678c307929 |
15 | 37b7365a2b |
hex | 1f7c761ab1 |
135232101041 has 32 divisors (see below), whose sum is σ = 150957727488. Its totient is φ = 120487628800.
The previous prime is 135232100999. The next prime is 135232101049. The reversal of 135232101041 is 140101232531.
It is a cyclic number.
It is not a de Polignac number, because 135232101041 - 226 = 135164992177 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a junction number, because it is equal to n+sod(n) for n = 135232100998 and 135232101016.
It is not an unprimeable number, because it can be changed into a prime (135232101049) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36537491 + ... + 36541191.
It is an arithmetic number, because the mean of its divisors is an integer number (4717428984).
Almost surely, 2135232101041 is an apocalyptic number.
It is an amenable number.
135232101041 is a deficient number, since it is larger than the sum of its proper divisors (15725626447).
135232101041 is a wasteful number, since it uses less digits than its factorization.
135232101041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4681.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 135232101041 its reverse (140101232531), we get a palindrome (275333333572).
The spelling of 135232101041 in words is "one hundred thirty-five billion, two hundred thirty-two million, one hundred one thousand, forty-one".
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