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13523245141 = 71931892163
BaseRepresentation
bin11001001100000110…
…00101100001010101
31021220110101000212011
430212003011201111
5210143422321031
610113522024221
7656055454450
oct144603054125
937813330764
1013523245141
11580a57925a
122754aa8071
131376905303
14924052497
1554235c6b1
hex3260c5855

13523245141 has 4 divisors (see below), whose sum is σ = 15455137312. Its totient is φ = 11591352972.

The previous prime is 13523245133. The next prime is 13523245159. The reversal of 13523245141 is 14154232531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13523245141 - 23 = 13523245133 is a prime.

It is a super-3 number, since 3×135232451413 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13529245141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 965946075 + ... + 965946088.

It is an arithmetic number, because the mean of its divisors is an integer number (3863784328).

Almost surely, 213523245141 is an apocalyptic number.

It is an amenable number.

13523245141 is a deficient number, since it is larger than the sum of its proper divisors (1931892171).

13523245141 is an equidigital number, since it uses as much as digits as its factorization.

13523245141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1931892170.

The product of its digits is 14400, while the sum is 31.

Adding to 13523245141 its reverse (14154232531), we get a palindrome (27677477672).

The spelling of 13523245141 in words is "thirteen billion, five hundred twenty-three million, two hundred forty-five thousand, one hundred forty-one".

Divisors: 1 7 1931892163 13523245141