1352434441117 has 4 divisors (see below), whose sum is σ = 1352442281536. Its totient is φ = 1352426600700.

The previous prime is 1352434441093. The next prime is 1352434441139. The reversal of 1352434441117 is 7111444342531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1352434441117 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1352434441117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1352434441157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3655509 + ... + 4008442.

It is an arithmetic number, because the mean of its divisors is an integer number (338110570384).

Almost surely, 2^{1352434441117} is an apocalyptic number.

It is an amenable number.

1352434441117 is a deficient number, since it is larger than the sum of its proper divisors (7840419).

1352434441117 is an equidigital number, since it uses as much as digits as its factorization.

1352434441117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7840418.

The product of its digits is 161280, while the sum is 40.

Adding to 1352434441117 its reverse (7111444342531), we get a palindrome (8463878783648).

The spelling of 1352434441117 in words is "one trillion, three hundred fifty-two billion, four hundred thirty-four million, four hundred forty-one thousand, one hundred seventeen".