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135244033 = 197118107
BaseRepresentation
bin10000000111110…
…10100100000001
3100102111002221021
420003322210001
5234110302113
621230425441
73231361321
oct1003724401
9312432837
10135244033
116a383931
1239362281
1322033672
1413d67281
15bd1748d
hex80fa901

135244033 has 4 divisors (see below), whose sum is σ = 142362160. Its totient is φ = 128125908.

The previous prime is 135244001. The next prime is 135244063. The reversal of 135244033 is 330442531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 330442531 = 1549721323.

It is a cyclic number.

It is not a de Polignac number, because 135244033 - 25 = 135244001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135243989 and 135244007.

It is not an unprimeable number, because it can be changed into a prime (135244063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3559035 + ... + 3559072.

It is an arithmetic number, because the mean of its divisors is an integer number (35590540).

Almost surely, 2135244033 is an apocalyptic number.

It is an amenable number.

135244033 is a deficient number, since it is larger than the sum of its proper divisors (7118127).

135244033 is an equidigital number, since it uses as much as digits as its factorization.

135244033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7118126.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 135244033 is about 11629.4468054160. The cubic root of 135244033 is about 513.3017020576.

Adding to 135244033 its reverse (330442531), we get a palindrome (465686564).

The spelling of 135244033 in words is "one hundred thirty-five million, two hundred forty-four thousand, thirty-three".

Divisors: 1 19 7118107 135244033