1352604343 has 4 divisors (see below), whose sum is σ = 1365736528. Its totient is φ = 1339472160.

The previous prime is 1352604329. The next prime is 1352604347. The reversal of 1352604343 is 3434062531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3434062531 = 30509 ⋅112559.

It is a cyclic number.

It is not a de Polignac number, because 1352604343 - 2⁵ = 1352604311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1352604347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6565938 + ... + 6566143.

It is an arithmetic number, because the mean of its divisors is an integer number (341434132).

Almost surely, 2^1352604343 is an apocalyptic number.

1352604343 is a deficient number, since it is larger than the sum of its proper divisors (13132185).

1352604343 is a wasteful number, since it uses less digits than its factorization.

1352604343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13132184.

The product of its (nonzero) digits is 25920, while the sum is 31.

The square root of 1352604343 is about 36777.7696849605. The cubic root of 1352604343 is about 1105.9196954099.

Adding to 1352604343 its reverse (3434062531), we get a palindrome (4786666874).

The spelling of 1352604343 in words is "one billion, three hundred fifty-two million, six hundred four thousand, three hundred forty-three".