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13526411113 = 23588104831
BaseRepresentation
bin11001001100011110…
…01010011101101001
31021220200022212202101
430212033022131221
5210200230123423
610114113533401
7656124411625
oct144617123551
937820285671
1013526411113
115811340966
122755b74261
131377473377
14924638185
155427857ad
hex3263ca769

13526411113 has 4 divisors (see below), whose sum is σ = 14114515968. Its totient is φ = 12938306260.

The previous prime is 13526411077. The next prime is 13526411141. The reversal of 13526411113 is 31111462531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31111462531 = 53587008727.

It is a cyclic number.

It is not a de Polignac number, because 13526411113 - 233 = 4936476521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13526411153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294052393 + ... + 294052438.

It is an arithmetic number, because the mean of its divisors is an integer number (3528628992).

Almost surely, 213526411113 is an apocalyptic number.

It is an amenable number.

13526411113 is a deficient number, since it is larger than the sum of its proper divisors (588104855).

13526411113 is an equidigital number, since it uses as much as digits as its factorization.

13526411113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 588104854.

The product of its digits is 2160, while the sum is 28.

Adding to 13526411113 its reverse (31111462531), we get a palindrome (44637873644).

The spelling of 13526411113 in words is "thirteen billion, five hundred twenty-six million, four hundred eleven thousand, one hundred thirteen".

Divisors: 1 23 588104831 13526411113