Base | Representation |
---|---|
bin | 10011101100000101011… |
… | …010001000100111100101 |
3 | 11210100100021102120002221 |
4 | 103230011122020213211 |
5 | 134131423342412430 |
6 | 2513321230032341 |
7 | 166515510305353 |
oct | 23540532104745 |
9 | 4710307376087 |
10 | 1353005435365 |
11 | 481896328321 |
12 | 19a27a9486b1 |
13 | 9a78470268c |
14 | 496b30d87d3 |
15 | 252dc58457a |
hex | 13b056889e5 |
1353005435365 has 8 divisors (see below), whose sum is σ = 1623635659800. Its totient is φ = 1082384923392.
The previous prime is 1353005435347. The next prime is 1353005435387. The reversal of 1353005435365 is 5635345003531.
It can be written as a sum of positive squares in 4 ways, for example, as 101663409409 + 1251342025956 = 318847^2 + 1118634^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1353005435365 - 25 = 1353005435333 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2118040 + ... + 2681809.
It is an arithmetic number, because the mean of its divisors is an integer number (202954457475).
Almost surely, 21353005435365 is an apocalyptic number.
It is an amenable number.
1353005435365 is a deficient number, since it is larger than the sum of its proper divisors (270630224435).
1353005435365 is an equidigital number, since it uses as much as digits as its factorization.
1353005435365 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4856231.
The product of its (nonzero) digits is 1215000, while the sum is 43.
The spelling of 1353005435365 in words is "one trillion, three hundred fifty-three billion, five million, four hundred thirty-five thousand, three hundred sixty-five".
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