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13531135433 = 29466590877
BaseRepresentation
bin11001001101000010…
…01011110111001001
31021221000012220022012
430212201023313021
5210202432313213
610114403105305
7656212516304
oct144641136711
937830186265
1013531135433
115813a78362
122757672235
13137843881a
14925107b3b
15542dba4a8
hex32684bdc9

13531135433 has 4 divisors (see below), whose sum is σ = 13997726340. Its totient is φ = 13064544528.

The previous prime is 13531135411. The next prime is 13531135469. The reversal of 13531135433 is 33453113531.

13531135433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4506705424 + 9024430009 = 67132^2 + 94997^2 .

It is a cyclic number.

It is not a de Polignac number, because 13531135433 - 216 = 13531069897 is a prime.

It is a super-2 number, since 2×135311354332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13531135433.

It is not an unprimeable number, because it can be changed into a prime (13531135333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233295410 + ... + 233295467.

It is an arithmetic number, because the mean of its divisors is an integer number (3499431585).

Almost surely, 213531135433 is an apocalyptic number.

It is an amenable number.

13531135433 is a deficient number, since it is larger than the sum of its proper divisors (466590907).

13531135433 is an equidigital number, since it uses as much as digits as its factorization.

13531135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466590906.

The product of its digits is 24300, while the sum is 32.

Adding to 13531135433 its reverse (33453113531), we get a palindrome (46984248964).

The spelling of 13531135433 in words is "thirteen billion, five hundred thirty-one million, one hundred thirty-five thousand, four hundred thirty-three".

Divisors: 1 29 466590877 13531135433