13531145041 has 4 divisors (see below), whose sum is σ = 13819041792. Its totient is φ = 13243248292.

The previous prime is 13531144999. The next prime is 13531145071. The reversal of 13531145041 is 14054113531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13531145041 - 2¹¹ = 13531142993 is a prime.

It is a super-2 number, since 2×13531145041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13531145071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143948305 + ... + 143948398.

It is an arithmetic number, because the mean of its divisors is an integer number (3454760448).

Almost surely, 2^13531145041 is an apocalyptic number.

It is an amenable number.

13531145041 is a deficient number, since it is larger than the sum of its proper divisors (287896751).

13531145041 is an equidigital number, since it uses as much as digits as its factorization.

13531145041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287896750.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 13531145041 its reverse (14054113531), we get a palindrome (27585258572).

The spelling of 13531145041 in words is "thirteen billion, five hundred thirty-one million, one hundred forty-five thousand, forty-one".