Base | Representation |
---|---|
bin | 11001001101000010… |
… | …11100001110000101 |
3 | 1021221000100022012211 |
4 | 30212201130032011 |
5 | 210202441434222 |
6 | 10114404343421 |
7 | 656213215534 |
oct | 144641341605 |
9 | 37830308184 |
10 | 13531202437 |
11 | 5814013735 |
12 | 27576a4b71 |
13 | 137846017c |
14 | 92512431b |
15 | 542dd0277 |
hex | 32685c385 |
13531202437 has 4 divisors (see below), whose sum is σ = 13629970476. Its totient is φ = 13432434400.
The previous prime is 13531202383. The next prime is 13531202449. The reversal of 13531202437 is 73420213531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9904031361 + 3627171076 = 99519^2 + 60226^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13531202437 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13531202399 and 13531202408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13531202467) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49383814 + ... + 49384087.
It is an arithmetic number, because the mean of its divisors is an integer number (3407492619).
Almost surely, 213531202437 is an apocalyptic number.
It is an amenable number.
13531202437 is a deficient number, since it is larger than the sum of its proper divisors (98768039).
13531202437 is an equidigital number, since it uses as much as digits as its factorization.
13531202437 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98768038.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 13531202437 its reverse (73420213531), we get a palindrome (86951415968).
The spelling of 13531202437 in words is "thirteen billion, five hundred thirty-one million, two hundred two thousand, four hundred thirty-seven".
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