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135313120000 = 28544120627
BaseRepresentation
bin111111000000101001…
…0100101101100000000
3110221021012111201002001
41332001102211230000
54204110124320000
6142054553433344
712530120354062
oct1760122455400
9427235451061
10135313120000
11524278018a3
122228410b854
13c9b5875c16
146798d97732
1537be51b46a
hex1f814a5b00

135313120000 has 180 divisors, whose sum is σ = 345762864216. Its totient is φ = 52802560000.

The previous prime is 135313119989. The next prime is 135313120027. The reversal of 135313120000 is 21313531.

It is a self number, because there is not a number n which added to its sum of digits gives 135313120000.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 6549687 + ... + 6570313.

Almost surely, 2135313120000 is an apocalyptic number.

135313120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135313120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172881432108).

135313120000 is an abundant number, since it is smaller than the sum of its proper divisors (210449744216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135313120000 is an frugal number, since it uses more digits than its factorization.

135313120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20704 (or 20675 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 135313120000 its reverse (21313531), we get a palindrome (135334433531).

The spelling of 135313120000 in words is "one hundred thirty-five billion, three hundred thirteen million, one hundred twenty thousand".