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135313685645 = 527062737129
BaseRepresentation
bin111111000000101010…
…0101111110010001101
3110221021020120102222212
41332001110233302031
54204110300420040
6142055013520205
712530125231145
oct1760124576215
9427236512885
10135313685645
1152428058876
1222284343065
13c9b5a13518
1467990a3925
1537be5cdd65
hex1f8152fc8d

135313685645 has 4 divisors (see below), whose sum is σ = 162376422780. Its totient is φ = 108250948512.

The previous prime is 135313685623. The next prime is 135313685671. The reversal of 135313685645 is 546586313531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102978093604 + 32335592041 = 320902^2 + 179821^2 .

It is a cyclic number.

It is not a de Polignac number, because 135313685645 - 212 = 135313681549 is a prime.

It is a super-3 number, since 3×1353136856453 (a number of 34 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 135313685593 and 135313685602.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13531368560 + ... + 13531368569.

It is an arithmetic number, because the mean of its divisors is an integer number (40594105695).

Almost surely, 2135313685645 is an apocalyptic number.

It is an amenable number.

135313685645 is a deficient number, since it is larger than the sum of its proper divisors (27062737135).

135313685645 is an equidigital number, since it uses as much as digits as its factorization.

135313685645 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27062737134.

The product of its digits is 3888000, while the sum is 50.

The spelling of 135313685645 in words is "one hundred thirty-five billion, three hundred thirteen million, six hundred eighty-five thousand, six hundred forty-five".

Divisors: 1 5 27062737129 135313685645