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135314201323 = 749391391379
BaseRepresentation
bin111111000000101011…
…0101101101011101011
3110221021021112122101001
41332001112231223223
54204110413420243
6142055032535431
712530132506450
oct1760126555353
9427237478331
10135314201323
1152428380254
1222284551577
13c9b5b64162
146799199827
1537be681a4d
hex1f815adaeb

135314201323 has 8 divisors (see below), whose sum is σ = 154648327680. Its totient is φ = 115980956520.

The previous prime is 135314201251. The next prime is 135314201327. The reversal of 135314201323 is 323102413531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135314201323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135314201291 and 135314201300.

It is not an unprimeable number, because it can be changed into a prime (135314201327) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150048 + ... + 541426.

It is an arithmetic number, because the mean of its divisors is an integer number (19331040960).

Almost surely, 2135314201323 is an apocalyptic number.

135314201323 is a deficient number, since it is larger than the sum of its proper divisors (19334126357).

135314201323 is an equidigital number, since it uses as much as digits as its factorization.

135314201323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440777.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 135314201323 its reverse (323102413531), we get a palindrome (458416614854).

The spelling of 135314201323 in words is "one hundred thirty-five billion, three hundred fourteen million, two hundred one thousand, three hundred twenty-three".

Divisors: 1 7 49391 345737 391379 2739653 19330600189 135314201323