Base | Representation |
---|---|
bin | 11001001101001100… |
… | …00110110001011001 |
3 | 1021221002122102200020 |
4 | 30212212012301121 |
5 | 210203300102210 |
6 | 10114450501053 |
7 | 656226501000 |
oct | 144646066131 |
9 | 37832572606 |
10 | 13532425305 |
11 | 5814779473 |
12 | 2757b94789 |
13 | 137879a969 |
14 | 925361c37 |
15 | 543072770 |
hex | 326986c59 |
13532425305 has 64 divisors (see below), whose sum is σ = 25297920000. Its totient is φ = 6174517440.
The previous prime is 13532425303. The next prime is 13532425307. The reversal of 13532425305 is 50352423531.
It is an interprime number because it is at equal distance from previous prime (13532425303) and next prime (13532425307).
It is not a de Polignac number, because 13532425305 - 21 = 13532425303 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13532425301) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3079660 + ... + 3084050.
It is an arithmetic number, because the mean of its divisors is an integer number (395280000).
Almost surely, 213532425305 is an apocalyptic number.
13532425305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13532425305 is a deficient number, since it is larger than the sum of its proper divisors (11765494695).
13532425305 is an equidigital number, since it uses as much as digits as its factorization.
13532425305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5019 (or 5005 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 13532425305 its reverse (50352423531), we get a palindrome (63884848836).
The spelling of 13532425305 in words is "thirteen billion, five hundred thirty-two million, four hundred twenty-five thousand, three hundred five".
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