Base | Representation |
---|---|
bin | 1100010011101100011111… |
… | …1111101011010110101011 |
3 | 1202220200202100121020110201 |
4 | 3010323013333223112223 |
5 | 3233204031044403120 |
6 | 44440425025453031 |
7 | 2564456010665566 |
oct | 304730777532653 |
9 | 52820670536421 |
10 | 13532502341035 |
11 | 4348113864067 |
12 | 16268337a1177 |
13 | 77215673a142 |
14 | 34ad95b534dd |
15 | 18702893340a |
hex | c4ec7feb5ab |
13532502341035 has 16 divisors (see below), whose sum is σ = 16316267800320. Its totient is φ = 10774493785440.
The previous prime is 13532502341021. The next prime is 13532502341051. The reversal of 13532502341035 is 53014320523531.
It is not a de Polignac number, because 13532502341035 - 25 = 13532502341003 is a prime.
It is a super-2 number, since 2×135325023410352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13532502340985 and 13532502341003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86789754 + ... + 86945536.
It is an arithmetic number, because the mean of its divisors is an integer number (1019766737520).
Almost surely, 213532502341035 is an apocalyptic number.
13532502341035 is a deficient number, since it is larger than the sum of its proper divisors (2783765459285).
13532502341035 is a wasteful number, since it uses less digits than its factorization.
13532502341035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238338.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 13532502341035 its reverse (53014320523531), we get a palindrome (66546822864566).
The spelling of 13532502341035 in words is "thirteen trillion, five hundred thirty-two billion, five hundred two million, three hundred forty-one thousand, thirty-five".
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