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13532502341051 is a prime number
BaseRepresentation
bin1100010011101100011111…
…1111101011010110111011
31202220200202100121020111022
43010323013333223112323
53233204031044403201
644440425025453055
72564456010665621
oct304730777532673
952820670536438
1013532502341051
114348113864081
1216268337a118b
1377215673a155
1434ad95b53511
1518702893341b
hexc4ec7feb5bb

13532502341051 has 2 divisors, whose sum is σ = 13532502341052. Its totient is φ = 13532502341050.

The previous prime is 13532502341021. The next prime is 13532502341063. The reversal of 13532502341051 is 15014320523531.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13532502341051 - 238 = 13257624434107 is a prime.

It is a super-2 number, since 2×135325023410512 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13532502341021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6766251170525 + 6766251170526.

It is an arithmetic number, because the mean of its divisors is an integer number (6766251170526).

Almost surely, 213532502341051 is an apocalyptic number.

13532502341051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13532502341051 is an equidigital number, since it uses as much as digits as its factorization.

13532502341051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 13532502341051 its reverse (15014320523531), we get a palindrome (28546822864582).

The spelling of 13532502341051 in words is "thirteen trillion, five hundred thirty-two billion, five hundred two million, three hundred forty-one thousand, fifty-one".