Base | Representation |
---|---|
bin | 1100010011101100011111… |
… | …1111101011010110111011 |
3 | 1202220200202100121020111022 |
4 | 3010323013333223112323 |
5 | 3233204031044403201 |
6 | 44440425025453055 |
7 | 2564456010665621 |
oct | 304730777532673 |
9 | 52820670536438 |
10 | 13532502341051 |
11 | 4348113864081 |
12 | 16268337a118b |
13 | 77215673a155 |
14 | 34ad95b53511 |
15 | 18702893341b |
hex | c4ec7feb5bb |
13532502341051 has 2 divisors, whose sum is σ = 13532502341052. Its totient is φ = 13532502341050.
The previous prime is 13532502341021. The next prime is 13532502341063. The reversal of 13532502341051 is 15014320523531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13532502341051 - 238 = 13257624434107 is a prime.
It is a super-2 number, since 2×135325023410512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13532502341021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6766251170525 + 6766251170526.
It is an arithmetic number, because the mean of its divisors is an integer number (6766251170526).
Almost surely, 213532502341051 is an apocalyptic number.
13532502341051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13532502341051 is an equidigital number, since it uses as much as digits as its factorization.
13532502341051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 13532502341051 its reverse (15014320523531), we get a palindrome (28546822864582).
The spelling of 13532502341051 in words is "thirteen trillion, five hundred thirty-two billion, five hundred two million, three hundred forty-one thousand, fifty-one".
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