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1353255345641 = 1678103325423
BaseRepresentation
bin10011101100010100010…
…011011101110111101001
311210100222200200022120002
4103230110103131313221
5134132431332030031
62513402114312345
7166524633434633
oct23542423356751
94710880608502
101353255345641
11481a043aa641
1219a32a5886b5
139a7c4413294
14496d838da53
152530449bccb
hex13b144ddde9

1353255345641 has 4 divisors (see below), whose sum is σ = 1361358671232. Its totient is φ = 1345152020052.

The previous prime is 1353255345601. The next prime is 1353255345649. The reversal of 1353255345641 is 1465435523531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1353255345641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1353255345649) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4051662545 + ... + 4051662878.

It is an arithmetic number, because the mean of its divisors is an integer number (340339667808).

Almost surely, 21353255345641 is an apocalyptic number.

It is an amenable number.

1353255345641 is a deficient number, since it is larger than the sum of its proper divisors (8103325591).

1353255345641 is an equidigital number, since it uses as much as digits as its factorization.

1353255345641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8103325590.

The product of its digits is 3240000, while the sum is 47.

The spelling of 1353255345641 in words is "one trillion, three hundred fifty-three billion, two hundred fifty-five million, three hundred forty-five thousand, six hundred forty-one".

Divisors: 1 167 8103325423 1353255345641