1353260141221 has 4 divisors (see below), whose sum is σ = 1424484359200. Its totient is φ = 1282035923244.

The previous prime is 1353260141141. The next prime is 1353260141239. The reversal of 1353260141221 is 1221410623531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1353260141221 - 2³⁹ = 803504327333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1353260141251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35612108961 + ... + 35612108998.

It is an arithmetic number, because the mean of its divisors is an integer number (356121089800).

Almost surely, 2^{1353260141221} is an apocalyptic number.

It is an amenable number.

1353260141221 is a deficient number, since it is larger than the sum of its proper divisors (71224217979).

1353260141221 is an equidigital number, since it uses as much as digits as its factorization.

1353260141221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71224217978.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 1353260141221 its reverse (1221410623531), we get a palindrome (2574670764752).

The spelling of 1353260141221 in words is "one trillion, three hundred fifty-three billion, two hundred sixty million, one hundred forty-one thousand, two hundred twenty-one".