13533104041 has 4 divisors (see below), whose sum is σ = 13538610000. Its totient is φ = 13527598084.

The previous prime is 13533104023. The next prime is 13533104059. The reversal of 13533104041 is 14040133531.

13533104041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13533104023) and next prime (13533104059).

It is a cyclic number.

It is not a de Polignac number, because 13533104041 - 2¹⁷ = 13532972969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13533103997 and 13533104015.

It is not an unprimeable number, because it can be changed into a prime (13533104341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2749291 + ... + 2754208.

It is an arithmetic number, because the mean of its divisors is an integer number (3384652500).

Almost surely, 2^13533104041 is an apocalyptic number.

It is an amenable number.

13533104041 is a deficient number, since it is larger than the sum of its proper divisors (5505959).

13533104041 is an equidigital number, since it uses as much as digits as its factorization.

13533104041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5505958.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13533104041 its reverse (14040133531), we get a palindrome (27573237572).

The spelling of 13533104041 in words is "thirteen billion, five hundred thirty-three million, one hundred four thousand, forty-one".