Base | Representation |
---|---|
bin | 10011101100011000010… |
… | …010011111110001010111 |
3 | 11210101011100110212201001 |
4 | 103230120102133301113 |
5 | 134133100440401101 |
6 | 2513412503244131 |
7 | 166526404621015 |
oct | 23543022376127 |
9 | 4711140425631 |
10 | 1353322200151 |
11 | 481a391123a9 |
12 | 19a348a49647 |
13 | 9a80522016c |
14 | 497031d38b5 |
15 | 2530a2a5901 |
hex | 13b1849fc57 |
1353322200151 has 4 divisors (see below), whose sum is σ = 1353407325304. Its totient is φ = 1353237075000.
The previous prime is 1353322200137. The next prime is 1353322200211. The reversal of 1353322200151 is 1510022233531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1353322200151 - 27 = 1353322200023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1353322200101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42538725 + ... + 42570526.
It is an arithmetic number, because the mean of its divisors is an integer number (338351831326).
Almost surely, 21353322200151 is an apocalyptic number.
1353322200151 is a deficient number, since it is larger than the sum of its proper divisors (85125153).
1353322200151 is an equidigital number, since it uses as much as digits as its factorization.
1353322200151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85125152.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1353322200151 its reverse (1510022233531), we get a palindrome (2863344433682).
The spelling of 1353322200151 in words is "one trillion, three hundred fifty-three billion, three hundred twenty-two million, two hundred thousand, one hundred fifty-one".
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