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1353322200151 = 1590185109251
BaseRepresentation
bin10011101100011000010…
…010011111110001010111
311210101011100110212201001
4103230120102133301113
5134133100440401101
62513412503244131
7166526404621015
oct23543022376127
94711140425631
101353322200151
11481a391123a9
1219a348a49647
139a80522016c
14497031d38b5
152530a2a5901
hex13b1849fc57

1353322200151 has 4 divisors (see below), whose sum is σ = 1353407325304. Its totient is φ = 1353237075000.

The previous prime is 1353322200137. The next prime is 1353322200211. The reversal of 1353322200151 is 1510022233531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1353322200151 - 27 = 1353322200023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1353322200101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42538725 + ... + 42570526.

It is an arithmetic number, because the mean of its divisors is an integer number (338351831326).

Almost surely, 21353322200151 is an apocalyptic number.

1353322200151 is a deficient number, since it is larger than the sum of its proper divisors (85125153).

1353322200151 is an equidigital number, since it uses as much as digits as its factorization.

1353322200151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85125152.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 1353322200151 its reverse (1510022233531), we get a palindrome (2863344433682).

The spelling of 1353322200151 in words is "one trillion, three hundred fifty-three billion, three hundred twenty-two million, two hundred thousand, one hundred fifty-one".

Divisors: 1 15901 85109251 1353322200151