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13533535040135 = 5112423101553559
BaseRepresentation
bin1100010011110000010110…
…0011000111001010000111
31202220210102022210210022112
43010330011203013022013
53233213134432241020
644441115320051235
72564523420536255
oct304740543071207
952823368723275
1013533535040135
1143485a37911a0
121626a81603b1b
1377228c6859b6
1434b052d735d5
151870894232c5
hexc4f058c7287

13533535040135 has 16 divisors (see below), whose sum is σ = 17723939719680. Its totient is φ = 9838508699040.

The previous prime is 13533535040101. The next prime is 13533535040173. The reversal of 13533535040135 is 53104053533531.

It is not a de Polignac number, because 13533535040135 - 28 = 13533535039879 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13533535040092 and 13533535040101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50643515 + ... + 50910044.

It is an arithmetic number, because the mean of its divisors is an integer number (1107746232480).

Almost surely, 213533535040135 is an apocalyptic number.

13533535040135 is a deficient number, since it is larger than the sum of its proper divisors (4190404679545).

13533535040135 is a wasteful number, since it uses less digits than its factorization.

13533535040135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101555998.

The product of its (nonzero) digits is 607500, while the sum is 41.

Adding to 13533535040135 its reverse (53104053533531), we get a palindrome (66637588573666).

The spelling of 13533535040135 in words is "thirteen trillion, five hundred thirty-three billion, five hundred thirty-five million, forty thousand, one hundred thirty-five".

Divisors: 1 5 11 55 2423 12115 26653 133265 101553559 507767795 1117089149 5585445745 246064273457 1230321367285 2706707008027 13533535040135