Base | Representation |
---|---|
bin | 1100010011110000010110… |
… | …0011000111001010000111 |
3 | 1202220210102022210210022112 |
4 | 3010330011203013022013 |
5 | 3233213134432241020 |
6 | 44441115320051235 |
7 | 2564523420536255 |
oct | 304740543071207 |
9 | 52823368723275 |
10 | 13533535040135 |
11 | 43485a37911a0 |
12 | 1626a81603b1b |
13 | 77228c6859b6 |
14 | 34b052d735d5 |
15 | 1870894232c5 |
hex | c4f058c7287 |
13533535040135 has 16 divisors (see below), whose sum is σ = 17723939719680. Its totient is φ = 9838508699040.
The previous prime is 13533535040101. The next prime is 13533535040173. The reversal of 13533535040135 is 53104053533531.
It is not a de Polignac number, because 13533535040135 - 28 = 13533535039879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13533535040092 and 13533535040101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50643515 + ... + 50910044.
It is an arithmetic number, because the mean of its divisors is an integer number (1107746232480).
Almost surely, 213533535040135 is an apocalyptic number.
13533535040135 is a deficient number, since it is larger than the sum of its proper divisors (4190404679545).
13533535040135 is a wasteful number, since it uses less digits than its factorization.
13533535040135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101555998.
The product of its (nonzero) digits is 607500, while the sum is 41.
Adding to 13533535040135 its reverse (53104053533531), we get a palindrome (66637588573666).
The spelling of 13533535040135 in words is "thirteen trillion, five hundred thirty-three billion, five hundred thirty-five million, forty thousand, one hundred thirty-five".
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