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13534003 = 713114759
BaseRepresentation
bin110011101000…
…001100110011
3221110121011101
4303220030303
511431042003
61202025231
7223015510
oct63501463
927417141
1013534003
11770432a
124648217
132a5b2b2
141b24307
1512c511d
hexce8333

13534003 has 8 divisors (see below), whose sum is σ = 15586560. Its totient is φ = 11511240.

The previous prime is 13533997. The next prime is 13534007. The reversal of 13534003 is 30043531.

13534003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13534003 - 221 = 11436851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13534007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6463 + ... + 8296.

It is an arithmetic number, because the mean of its divisors is an integer number (1948320).

Almost surely, 213534003 is an apocalyptic number.

13534003 is a deficient number, since it is larger than the sum of its proper divisors (2052557).

13534003 is a wasteful number, since it uses less digits than its factorization.

13534003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14897.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 13534003 is about 3678.8589263520. The cubic root of 13534003 is about 238.3099027721.

Adding to 13534003 its reverse (30043531), we get a palindrome (43577534).

It can be divided in two parts, 1353 and 4003, that added together give a triangular number (5356 = T103).

The spelling of 13534003 in words is "thirteen million, five hundred thirty-four thousand, three".

Divisors: 1 7 131 917 14759 103313 1933429 13534003