Base | Representation |
---|---|
bin | 11001001101011001… |
… | …00011000111111101 |
3 | 1021221012211020112122 |
4 | 30212230203013331 |
5 | 210204213124201 |
6 | 10114551012325 |
7 | 656250034121 |
oct | 144654430775 |
9 | 37835736478 |
10 | 13534114301 |
11 | 5815722434 |
12 | 275866a0a5 |
13 | 1378c3c676 |
14 | 925681581 |
15 | 5432a7e1b |
hex | 326b231fd |
13534114301 has 4 divisors (see below), whose sum is σ = 13899901212. Its totient is φ = 13168327392.
The previous prime is 13534114289. The next prime is 13534114343. The reversal of 13534114301 is 10341143531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13025656900 + 508457401 = 114130^2 + 22549^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13534114301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13534114351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182893400 + ... + 182893473.
It is an arithmetic number, because the mean of its divisors is an integer number (3474975303).
Almost surely, 213534114301 is an apocalyptic number.
It is an amenable number.
13534114301 is a deficient number, since it is larger than the sum of its proper divisors (365786911).
13534114301 is an equidigital number, since it uses as much as digits as its factorization.
13534114301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 365786910.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 13534114301 its reverse (10341143531), we get a palindrome (23875257832).
The spelling of 13534114301 in words is "thirteen billion, five hundred thirty-four million, one hundred fourteen thousand, three hundred one".
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