Base | Representation |
---|---|
bin | 10011101100011111011… |
… | …100010110100000011001 |
3 | 11210101110201022201200110 |
4 | 103230133130112200121 |
5 | 134133322202133103 |
6 | 2513432431554533 |
7 | 166532363042145 |
oct | 23543734264031 |
9 | 4711421281613 |
10 | 1353442224153 |
11 | 481a9a940198 |
12 | 19a38108ba49 |
13 | 9a824054c96 |
14 | 49715118225 |
15 | 25315ab3403 |
hex | 13b1f716819 |
1353442224153 has 4 divisors (see below), whose sum is σ = 1804589632208. Its totient is φ = 902294816100.
The previous prime is 1353442224131. The next prime is 1353442224157. The reversal of 1353442224153 is 3514222443531.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1353442224153 - 28 = 1353442223897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1353442224157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225573704023 + ... + 225573704028.
It is an arithmetic number, because the mean of its divisors is an integer number (451147408052).
Almost surely, 21353442224153 is an apocalyptic number.
It is an amenable number.
1353442224153 is a deficient number, since it is larger than the sum of its proper divisors (451147408055).
1353442224153 is an equidigital number, since it uses as much as digits as its factorization.
1353442224153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 451147408054.
The product of its digits is 345600, while the sum is 39.
Adding to 1353442224153 its reverse (3514222443531), we get a palindrome (4867664667684).
The spelling of 1353442224153 in words is "one trillion, three hundred fifty-three billion, four hundred forty-two million, two hundred twenty-four thousand, one hundred fifty-three".
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