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13535402053 = 113291194757
BaseRepresentation
bin11001001101100010…
…11101100001000101
31021221022020200000011
430212301131201011
5210210030331203
610115034350221
7656264006365
oct144661354105
937838220004
1013535402053
115816421998
122758b8b371
1313792a0854
149258d89a5
1554345e76d
hex326c5d845

13535402053 has 4 divisors (see below), whose sum is σ = 13536608140. Its totient is φ = 13534195968.

The previous prime is 13535402021. The next prime is 13535402059. The reversal of 13535402053 is 35020453531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9789717249 + 3745684804 = 98943^2 + 61202^2 .

It is a cyclic number.

It is not a de Polignac number, because 13535402053 - 25 = 13535402021 is a prime.

It is a super-2 number, since 2×135354020532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13535402059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 586050 + ... + 608707.

It is an arithmetic number, because the mean of its divisors is an integer number (3384152035).

Almost surely, 213535402053 is an apocalyptic number.

It is an amenable number.

13535402053 is a deficient number, since it is larger than the sum of its proper divisors (1206087).

13535402053 is a wasteful number, since it uses less digits than its factorization.

13535402053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1206086.

The product of its (nonzero) digits is 27000, while the sum is 31.

Adding to 13535402053 its reverse (35020453531), we get a palindrome (48555855584).

The spelling of 13535402053 in words is "thirteen billion, five hundred thirty-five million, four hundred two thousand, fifty-three".

Divisors: 1 11329 1194757 13535402053