Base | Representation |
---|---|
bin | 11110110001101010011110… |
… | …001100000010010010111010 |
3 | 122202020201222122020201122021 |
4 | 132301222132030002102322 |
5 | 120220121002322241102 |
6 | 1155512515140345054 |
7 | 40340010402053053 |
oct | 3661523614022272 |
9 | 582221878221567 |
10 | 135354253321402 |
11 | 3a14546435a395 |
12 | 132206896a518a |
13 | 5a6ab0b47289b |
14 | 255d27622d72a |
15 | 109ad1c432137 |
hex | 7b1a9e3024ba |
135354253321402 has 48 divisors (see below), whose sum is σ = 204570987446952. Its totient is φ = 67167093611520.
The previous prime is 135354253321291. The next prime is 135354253321411. The reversal of 135354253321402 is 204123352453531.
It can be written as a sum of positive squares in 4 ways, for example, as 67271803359721 + 68082449961681 = 8201939^2 + 8251209^2 .
It is a super-2 number, since 2×1353542533214022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 56847648252 + ... + 56847650632.
Almost surely, 2135354253321402 is an apocalyptic number.
135354253321402 is a deficient number, since it is larger than the sum of its proper divisors (69216734125550).
135354253321402 is an equidigital number, since it uses as much as digits as its factorization.
135354253321402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4031 (or 3652 counting only the distinct ones).
The product of its (nonzero) digits is 1296000, while the sum is 43.
The spelling of 135354253321402 in words is "one hundred thirty-five trillion, three hundred fifty-four billion, two hundred fifty-three million, three hundred twenty-one thousand, four hundred two".
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