1353544543153 has 4 divisors (see below), whose sum is σ = 1476594047088. Its totient is φ = 1230495039220.

The previous prime is 1353544543129. The next prime is 1353544543193. The reversal of 1353544543153 is 3513454453531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1353544543153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1353544543123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61524751951 + ... + 61524751972.

It is an arithmetic number, because the mean of its divisors is an integer number (369148511772).

Almost surely, 2^{1353544543153} is an apocalyptic number.

It is an amenable number.

1353544543153 is a deficient number, since it is larger than the sum of its proper divisors (123049503935).

1353544543153 is a wasteful number, since it uses less digits than its factorization.

1353544543153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123049503934.

The product of its digits is 3240000, while the sum is 46.

Adding to 1353544543153 its reverse (3513454453531), we get a palindrome (4866998996684).

The spelling of 1353544543153 in words is "one trillion, three hundred fifty-three billion, five hundred forty-four million, five hundred forty-three thousand, one hundred fifty-three".