Base | Representation |
---|---|
bin | 10011101100100101100… |
… | …010101010101110011001 |
3 | 11210101201211212001221011 |
4 | 103230211202222232121 |
5 | 134134024400340004 |
6 | 2513450525013521 |
7 | 166535044533202 |
oct | 23544542525631 |
9 | 4711654761834 |
10 | 1353544543129 |
11 | 482042675a29 |
12 | 19a3ab3b42a1 |
13 | 9a83c2cb15c |
14 | 497249505a9 |
15 | 2531ea75004 |
hex | 13b258aab99 |
1353544543129 has 2 divisors, whose sum is σ = 1353544543130. Its totient is φ = 1353544543128.
The previous prime is 1353544543123. The next prime is 1353544543193. The reversal of 1353544543129 is 9213454453531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1183613443600 + 169931099529 = 1087940^2 + 412227^2 .
It is a cyclic number.
It is not a de Polignac number, because 1353544543129 - 227 = 1353410325401 is a prime.
It is a super-2 number, since 2×13535445431292 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1353544543123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676772271564 + 676772271565.
It is an arithmetic number, because the mean of its divisors is an integer number (676772271565).
Almost surely, 21353544543129 is an apocalyptic number.
It is an amenable number.
1353544543129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353544543129 is an equidigital number, since it uses as much as digits as its factorization.
1353544543129 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3888000, while the sum is 49.
The spelling of 1353544543129 in words is "one trillion, three hundred fifty-three billion, five hundred forty-four million, five hundred forty-three thousand, one hundred twenty-nine".
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