Base | Representation |
---|---|
bin | 10011101100101001011… |
… | …100111000101101101111 |
3 | 11210101220102021120000201 |
4 | 103230221130320231233 |
5 | 134134143143331211 |
6 | 2513501230534331 |
7 | 166536502214260 |
oct | 23545134705557 |
9 | 4711812246021 |
10 | 1353610136431 |
11 | 4820766a7173 |
12 | 19a4093673a7 |
13 | 9a84ca85c67 |
14 | 4972d546967 |
15 | 253256d00c1 |
hex | 13b29738b6f |
1353610136431 has 4 divisors (see below), whose sum is σ = 1546983013072. Its totient is φ = 1160237259792.
The previous prime is 1353610136401. The next prime is 1353610136447. The reversal of 1353610136431 is 1346310163531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1353610136431 - 213 = 1353610128239 is a prime.
It is a super-2 number, since 2×13536101364312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1353610136401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96686438310 + ... + 96686438323.
It is an arithmetic number, because the mean of its divisors is an integer number (386745753268).
Almost surely, 21353610136431 is an apocalyptic number.
1353610136431 is a deficient number, since it is larger than the sum of its proper divisors (193372876641).
1353610136431 is an equidigital number, since it uses as much as digits as its factorization.
1353610136431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193372876640.
The product of its (nonzero) digits is 58320, while the sum is 37.
Adding to 1353610136431 its reverse (1346310163531), we get a palindrome (2699920299962).
The spelling of 1353610136431 in words is "one trillion, three hundred fifty-three billion, six hundred ten million, one hundred thirty-six thousand, four hundred thirty-one".
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