Base | Representation |
---|---|
bin | 11001001110000001… |
… | …10000110110111001 |
3 | 1021221120210110120210 |
4 | 30213000300312321 |
5 | 210212042212213 |
6 | 10115300341333 |
7 | 656343054360 |
oct | 144700606671 |
9 | 37846713523 |
10 | 13539413433 |
11 | 5818711787 |
12 | 275a3a4849 |
13 | 137a076650 |
14 | 9262607d7 |
15 | 5439a30c3 |
hex | 327030db9 |
13539413433 has 32 divisors (see below), whose sum is σ = 23387929600. Its totient is φ = 6765788736.
The previous prime is 13539413389. The next prime is 13539413453. The reversal of 13539413433 is 33431493531.
It is not a de Polignac number, because 13539413433 - 26 = 13539413369 is a prime.
It is a super-2 number, since 2×135394134332 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 13539413391 and 13539413400.
It is not an unprimeable number, because it can be changed into a prime (13539413453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1299943 + ... + 1310316.
It is an arithmetic number, because the mean of its divisors is an integer number (730872800).
Almost surely, 213539413433 is an apocalyptic number.
13539413433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13539413433 is a deficient number, since it is larger than the sum of its proper divisors (9848516167).
13539413433 is a wasteful number, since it uses less digits than its factorization.
13539413433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2610301.
The product of its digits is 174960, while the sum is 39.
The spelling of 13539413433 in words is "thirteen billion, five hundred thirty-nine million, four hundred thirteen thousand, four hundred thirty-three".
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